working on choose one problem
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8cf4a7d955
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1 changed files with 37 additions and 1 deletions
36
encode.py
36
encode.py
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@ -1,6 +1,7 @@
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import jdecode
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import jdecode
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import re
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import re
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import codecs
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import codecs
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import sys
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#badwords = []
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#badwords = []
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@ -467,6 +468,40 @@ def fix_x(s):
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return s
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return s
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# run after fixing dashes, it makes the regexes better, but before replacing newlines
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def reformat_choice(s):
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# the idea is to take 'choose n ~\n=ability\n=ability\n'
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# to '[n = ability = ability]\n'
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single_choices = re.findall(r'choose one', s)
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for choice in single_choices:
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print choice
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print s
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# since we have two groups in that regex
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newchoice = choice
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# newchoice = newchoice.replace('choose one ~', unary_marker + (unary_counter * 1))
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# newchoice = newchoice.replace('\n', ' ')
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# # the indexing cuts off the | we know is at the end
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# newchoice = '[' + newchoice[:-1] + ']|'
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s = s.replace(choice, newchoice)
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double_choices = re.findall(r'choose two ~[^|]*=[^\n|]*\|', s)
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for choice in double_choices:
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# since we have two groups in that regex
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newchoice = choice
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newchoice = newchoice.replace('choose two ~', unary_marker + (unary_counter * 2))
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newchoice = newchoice.replace('\n', ' ')
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# the indexing cuts off the | we know is at the end
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newchoice = '[' + newchoice[:-1] + ']|'
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s = s.replace(choice, newchoice)
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# sys.stdout.write('.')
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return s
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# do before removing newlines
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# do before removing newlines
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# might as well do this after countertype because we probably care more about
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# might as well do this after countertype because we probably care more about
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# the location of the equip cost
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# the location of the equip cost
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@ -525,6 +560,7 @@ def encode(card):
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text = fix_x(text)
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text = fix_x(text)
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text = replace_counters(text)
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text = replace_counters(text)
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text = rename_uncast(text)
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text = rename_uncast(text)
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text = reformat_choice(text)
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text = relocate_equip(text)
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text = relocate_equip(text)
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text = replace_newlines(text)
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text = replace_newlines(text)
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encoding += text
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encoding += text
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